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The volume of 10 "moles" of an ideal gas...

The volume of `10 "moles"` of an ideal gas at `10 atm` and `500 K` is

A

`82 L`

B

`41 L`

C

`20.5 L`

D

`(82)/(3)L`

Text Solution

Verified by Experts

The correct Answer is:
B
`n= 10 mol e`
`P=10 atm`
`T= 500K`
`R= 0.0821 L- atm K^(-1)mol^(-1)`
`PV= nRT`
`10xxV= 10xx0.082xx500`
`V= 41L`
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