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The ratio between enrgies of 16 g of O(2...

The ratio between enrgies of `16 g` of `O_(2)` and `28 g` of `N_(2)` respectively at `300 K` will be

A

`1:1`

B

`1:2`

C

`2:1`

D

`4:7`

Text Solution

Verified by Experts

The correct Answer is:
B
Number of moles of `O_(2)= (16)/(32) =(1)/(2)`
Number of moles of `N_(2)=(28)/(28)=1`
Ratio between number of moles `(1)/(2):1`
`KE` will be in the ratio `1:2`
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