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The pressure exerted by 6.0 g of methane...

The pressure exerted by `6.0 g` of methane gas in a `0.03 m^(3)` vessel at `129^(@)C` is: (Atomic masses of `C= 12.01, H= 1.01 and R= 8.314 JK^(-1)mol^(-1)`)

A

`215216 Pa`

B

`13409 Pa`

C

`41648 Pa`

D

`31684 Pa`

Text Solution

Verified by Experts

The correct Answer is:
C
`PV=(w)/(M)RT`
`Pxx0.03 =(6)/(16.05)xx8.314xx402`
`:. P=41647.7 Pa`
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