A bubble of air is underwater at temperature `15^(@)C` and the pressure `1.5` bar. If the bubble rises to the surface where the temperature is `25^(@)C` and the pressure is `1.0` bar, what will happen to the volume of the bubble?

Options

A. Volume will become smaller by a factor of `0.70`
B. Volume will become greater by a factor of `1.1`
C. Volume will become greater by a factor of `1.6`
D. Volume will become greater by a factor of `2.5`

Answer

C

Explanation

Given
`P_(1)= 1.5 ba r, T_(1)= 273+15= 288K, V_(1)=V`
`P_(2)= 1.0 ba r, T_(1)= 273+25= 298K, V_(2)=?`
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))Z`
`(1.5xxV)/(288)=(1xxV_(2))/(298)`
`V_(2)= 1.55 V`, i.e., volume of bubble will be almost `1.6` time to initial volume of bubble.