At `100^(@)C` and 1 atm, if the density of the liquid water is `1.0 g cm^(-3)` and that of water vapour is `0.0006 g cm^(-3)` , then the volume occupied by water molecules in `1 L` steam at this temperature is

Options

A. `6 c c`
B. `60 c c`
C. `0.6 c c`
D. `0.06 c c`

Answer

C

Explanation

Mass of `1L` water water vapour `=Vxxd= 1000xx0.0006= 0.6g`
`:.` volume of liquid water `=(0.6)/(1)= 0.6 c c`