The ratio between the root mean square speed of `H_(2)` at `50 K` and that of `O_(2)` at `800 K` is

Options

A. 4
B. 2
C. 1
D. `1//4`

Answer

C

Explanation

`V_(rms)(H_(2) at 50 K)=sqrt((3Rxx50)/(2xx10^(-3)))`
`V_(rms)(O_(2) at 800 K)=sqrt((3Rxx800)/(3xx10^(-3)))`
`(V_(rms)(H_(2)))/(V_(rms)(O_(2)))=(sqrt((3Rxx50)/(2xx10^(-3))))/(sqrt((3Rxx800)/(32xx10^(-3))))=(sqrt(25xx10^(3)))/(sqrt(25xx10^(3)))=1`