`XmL` of `H_(2)` gas effuses through a hole in a container is 5 second. The time taken for the effusion of the same volume of the gas specified below under identical conditions is .

Options

A. `10` seconds: `He`
B. `20` seconds: `O_(2)`
C. `25` seconds: `CO`
D. `35` seconds: `CO_(2)`

Answer

B

Explanation

`(r_(H_(2)))/(r_(H_(e)))=sqrt((4)/(2))=sqrt(2)`
`:.` (a) in incorrect
`(r_(H_(2)))/(r_(O_(2)))=sqrt((32)/(2))=4`
(b) is correct
`(r_(H_(2)))/(r_(C_(O)))=sqrt((28)/(2))=sqrt(14)`
(c) is correct
`(r_(H_(2)))/(r_(Co_(2)))=sqrt((2)/(44))=sqrt((1)/(12))`
(d) is correct.