`0.2` mole sample of hydrocarbon `C_(x)H_(y)` yields after complete combustion with excess `O_(2)` gas, `0.8` mole of `CO_(2) 1.1` mole of `H_(2)O`. Hence hydrocarbon is

Options

A. `C_(4)H_(10)`
B. `C_(4)H_(8)`
C. `C_(4)H_(5)`
D. `C_(8)H_(16)`

Answer

A

Explanation

`{:(C_(x)H_(y)+O_(2),rarr,xCO_(2)+(y)/(2)H_(2)O,),(0.2,,,),(0,,0.2x (y)/(x) xx 0.2,):}`
given `0.2x=8`
`x=4`
`0.1y=0.1`
`y= 10`
`:. C_(4)H_(10)`