The difference between the heats of reaction at constant pressure and a constant volume for the reaction `2C_(6)H_(6)(l) + 15O_(2)(g) rarr 12CO_(2)(g) + 6H_(2)O(l)` at `25^(@)C` in `kJ` is

Options

A. `-7.43`
B. `3.72`
C. `-3.72`
D. `7.43`

Answer

A

Explanation

For the reaction
`2C_(6)H_(6)(l)+150_(2)(g)rarr12CO_(2)(g)+H_(2)O(l)`
Here `Deltan=12-15=-3`
As we know, `DeltaH=DeltaE+DeltanRT`
or, `DeltaH-DeltaE=DeltanRT=-3xx298=-7.43KJ`