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Evaluate DeltaU at 500K for the process ...

Evaluate `DeltaU` at `500K` for the process
`Mg(s)+2HC1(g)=MgC1_(2)(s)+H_(2)(g)`
`DeltaH=-109Kcal`
The volume change of solids to be ignored

A

`-204Kcal`

B

`-108Kcal`

C

`-9Kcal`

D

`+9Kcal`

Text Solution

Verified by Experts

The correct Answer is:
C
`DeltaH=DeltaV+Deltan_(g)RT`
`-109=DeltaV+((-1xx2xx500)/(1000))Kcal`
`-109=DeltaU-1Kcal`
`DeltaU=-109+1=-108Kcal`
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