A particular state of system is arrived at starting from a given state in two different ways `(1)` following reversible path and `(2)` irreversible path. Which of the following relations would be correct if the processes are isothermal ?

Options

A. `DeltaS_(rev)ne DeltaS_(irrev)`
B. `Deltaq_(rev) = Deltaq_(irrev)`
C. `DeltaS_(rev) = DeltaS_(irrev)=(Deltaq_(rev))/(T)`
D. `DeltaS_(irrev)=(Deltaq_(irrev))/(T)ne DeltaS_(rev)`

Answer

B

Explanation

Since entropy is a state function, bence,
`DeltaS_(rev)=DeltaS_(irrev)=(Deltaq_(rev))/(T)`