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At 500K , for an isobaric pracess. Del...

At `500K` , for an isobaric pracess.
`DeltaS_(system)=-10(KJ)/(molK)` and `DeltaS_(surr)=12(KJ)/(mol K)`
Therefore, `DeltaG` for the entire process is

A

`-500KJ//mol`

B

`-1000KJ//mol`

C

`-600KJ//mol`

D

`-1100KJ//mol`

Text Solution

Verified by Experts

The correct Answer is:
D
`DeltaS_("total")=DeltaS_("system")-(DeltaH)/(T)=2KJ//mol`
or `(DeltaH-TDeltaS)/(T)=-2KJ//mol`
or `DeltaH-TDeltaS=-2TKJ//mol=-2xx500KJ//mol`
`=-1000(KJ)/(mol)`
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