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If the enthalpy of vaporization for wate...

If the enthalpy of vaporization for water is `198.5KJ mol^(-1)` , the entropy of its vaprization will be

A

`0.5KJ^(-1)`

B

`1.0KJK^(-1)mol^(-1)`

C

`1.5KJK^(-1)mol^(-1)`

D

`2.0KJK^(-1)mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
The minimum temperature required for the vaporization of `H_(2)O` is `100^(@)C` (or `373K`)
` therefore Delta_(v)S=(Delta_(v)H)/(T)`
`=(189.5)/(737)=0.5KJK^(-1)mol^(-1)`
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