`10ml` of `1 M H_(2)SO_(4)` will completely neutralise

Options

A. `10 ml` of `1M NaOH` solution
B. `10 ml` of `2 M NaOH` solution
C. `5 ml` of `2 M KOH` solution
D. `5 ml` of `1 M Na_(2)CO_(3)` solution

Answer

B

Explanation

`H_(2)SO_(4)+2H_(2)OhArr2H_(3)O^(+)+SO_(4)^(--)`
`NaOHhArrNa^(+)+OH^(-)`
`1` mole of `H_(2)SO_(4)` acid gives `2` moles of `H_(3)O^(+) ions`. So
`2` moles of `OH^(-)` are required for complete neutralization.