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The dissociation constant of weak acid H...

The dissociation constant of weak acid `HA` is `4.9xx10^(-8)`. After making the necessary approximations, calculate `pH` in `0.1 M` acid.

A

`1.155`

B

`2.155`

C

`3.155`

D

`4.155`

Text Solution

Verified by Experts

The correct Answer is:
D
For weak acid `K_(a)=alpha^(2).C`
`:. alpha=sqrt((K_(a))/(C))=sqrt((4.9xx10^(-8))/(0.1))=7xx10^(-4)`
`pH= -logH^(+)= -log alpha C`
`= -log7xx10^(-4)xx10-1`
`= 4.1549=4.155`
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