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Ammonia gas dissolves in water to form N...

Ammonia gas dissolves in water to form `NH_(4)OH`. In this reaction water acts as

A

A conjugate base

B

A non-polar solvent

C

An acid

D

A base

Text Solution

Verified by Experts

The correct Answer is:
C

`underset(Acid)(H_(2)O)+underset(base)(NH_(3))hArrNH_(4)^(+)+OH^(-)`.
In this reaction `H_(2)O` acts as acid because it donets a proton.
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A2Z-IONIC EQUILIBIUM-Section D - Chapter End Test
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  5. If an acidic indicator HIn ionies as HInhArrH^(+)+In^(-). To which max...

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  6. Let the solubilities of AgCl in pure water be 0.01 M CaCl(2), 0.01 M N...

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  9. The hydrolysis constant for ZnCl(2) will be where K(b) is effective ...

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  10. In which case pH will not change on dilution

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  12. 1 M benzoic acid (pKa=4.20) and 1 M C6H5COONa solutions are given sepa...

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  13. The pH of an aqueous solution of 0.1 M solution of a weak monoprotic a...

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  14. pH of a 10^(-10) M NaOH is nearest to

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  15. The dissocication constant of a weak acid is 1.0xx10^(-5), the equilib...

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  16. The pH of 0.1 M solution of the following salts increases in the order

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  17. In the equilibrium A^(-)+H(2)OhArrHA+OH^(-)(K(a)=1.0xx10^(-5)). The de...

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  19. The K(sp) of CuS, Ag(2)S and HgS are 10^(-31), 10^(-44) and 10^(-54) r...

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