Equal volumes of three acid solutions of `pH 3, 4` and `5` are mixed in a vessel. What will be the `H^(+)` ion concentration in the mixture?

Options

A. `3.7xx10^(-3) M`
B. `1.11xx10^(-3) M`
C. `1.11xx10^(-4) M`
D. `3.7xx10^(-4) M`

Answer

D

Explanation

`[H^(+)]=10^(-3) M, [H^(+)]=10^(-4) M, [H^(+)]= 10^(-5) M` for the given acids.
`M_(mix)V_(mix)=M_(1)V_(1)+M_(2)V_(2)+M_(3)V_(3)`
` M_(mix)xx3=10^(-3)xx1+10^(-4)xx1+10^(-5)xx1`
`M_(mix)=(10^(-5)[100+10+1])/(3)=(111xx10^(-5))/(3)`
`=37xx10^(-5) M=3.7xx10^(-4) M`