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2H(2)OhArrH(3)O^(+)+OH^(-) K(w)=1xx10^...

`2H_(2)OhArrH_(3)O^(+)+OH^(-)`
`K_(w)=1xx10^(-14)` at `25^(@)C`. Hence, `K_(a)` is:

A

`1xx10^(-14)`

B

`5.55xx10^(-13)`

C

`1.8xx10^(-16)`

D

`1.00xx10^(-7)`

Text Solution

Verified by Experts

The correct Answer is:
C
`K_(w)=[H^(+)][OH^(-)]=1xx10^(-14)`
`:. [H^(+)]=1xx10^(-7) M`,
`C= 1g//mL=1000 g//L=55.55 M`
Also in weak acid `[H^(+)]=sqrt(K_(a)C)`
`:. K_(a)=([H^(+)]^(2)]/(C )=(10^(-14))/(55.55)=1.8xx10^(-16)`
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