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A solution is prepared by dissolving 5.6...

A solution is prepared by dissolving `5.6 g` of `KOH` per litre of solution. `pOH` of the solution would be

A

`10^(-0.1)`

B

`10^(-1)`

C

`1`

D

`13`

Text Solution

Verified by Experts

The correct Answer is:
C
`[KOH]=(5.6)/(56)=0.1 M=[OH-]`
`pOH= -log[OH^(-)]= -log (10^(-1))=1`
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