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At 30^(@) C the solubility of Ag(2)CO(3)...

At `30^(@) C` the solubility of `Ag_(2)CO_(3) (K_(SP)=8xx10^(-12))` would be gretest in one litre of:

A

`0.05 M Na_(2)CO_(3)`

B

`0.05 M AgNO_(3)`

C

pure water

D

`0.05 M K_(2)CO_(3)`

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The correct Answer is:
To determine the greatest solubility of \( \text{Ag}_2\text{CO}_3 \) (silver carbonate) at \( 30^\circ C \) in one litre of different solutions, we need to consider the common ion effect. The solubility product constant (\( K_{sp} \)) for \( \text{Ag}_2\text{CO}_3 \) is given as \( 8 \times 10^{-12} \). ### Step-by-Step Solution: 1. **Identify the dissociation of \( \text{Ag}_2\text{CO}_3 \)**: \[ \text{Ag}_2\text{CO}_3 (s) \rightleftharpoons 2 \text{Ag}^+ (aq) + \text{CO}_3^{2-} (aq) \] From this equation, we can see that one mole of \( \text{Ag}_2\text{CO}_3 \) produces 2 moles of \( \text{Ag}^+ \) ions and 1 mole of \( \text{CO}_3^{2-} \) ions. 2. **Write the expression for \( K_{sp} \)**: \[ K_{sp} = [\text{Ag}^+]^2 [\text{CO}_3^{2-}] \] Substituting the solubility \( s \) for \( \text{Ag}_2\text{CO}_3 \): \[ K_{sp} = (2s)^2 (s) = 4s^3 \] 3. **Set up the equation using \( K_{sp} \)**: \[ 4s^3 = 8 \times 10^{-12} \] Solving for \( s \): \[ s^3 = \frac{8 \times 10^{-12}}{4} = 2 \times 10^{-12} \] \[ s = \sqrt[3]{2 \times 10^{-12}} \approx 1.26 \times 10^{-4} \text{ mol/L} \] 4. **Consider the effect of common ions**: - In solutions like sodium carbonate (\( \text{Na}_2\text{CO}_3 \)) or potassium carbonate (\( \text{K}_2\text{CO}_3 \)), there are carbonate ions (\( \text{CO}_3^{2-} \)) present. The presence of these ions will shift the equilibrium to the left, decreasing the solubility of \( \text{Ag}_2\text{CO}_3 \). - In the case of silver nitrate (\( \text{AgNO}_3 \)), silver ions (\( \text{Ag}^+ \)) are present, which will also decrease the solubility of \( \text{Ag}_2\text{CO}_3 \). 5. **Conclusion**: The solubility of \( \text{Ag}_2\text{CO}_3 \) will be greatest in pure water since there are no common ions present to affect the solubility. ### Final Answer: The greatest solubility of \( \text{Ag}_2\text{CO}_3 \) at \( 30^\circ C \) would be in pure water.

To determine the greatest solubility of \( \text{Ag}_2\text{CO}_3 \) (silver carbonate) at \( 30^\circ C \) in one litre of different solutions, we need to consider the common ion effect. The solubility product constant (\( K_{sp} \)) for \( \text{Ag}_2\text{CO}_3 \) is given as \( 8 \times 10^{-12} \). ### Step-by-Step Solution: 1. **Identify the dissociation of \( \text{Ag}_2\text{CO}_3 \)**: \[ \text{Ag}_2\text{CO}_3 (s) \rightleftharpoons 2 \text{Ag}^+ (aq) + \text{CO}_3^{2-} (aq) \] ...
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A2Z-IONIC EQUILIBIUM-Common Ion Effect, Ksp And Applications
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  12. Solubility of calcium phosphate (molecular mass, M) in water is W g pe...

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  13. The K(sp) of Mg(OH)(2) is 1xx10^(-12). 0.01 M Mg(OH)(2) will precipita...

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  14. A salt M(2) X(3) dissolves in water such that is solubility is x.g."mo...

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