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What fraction of an indicator H"in" is i...

What fraction of an indicator `H"in"` is in the basic form at a `pH` of `6` if `pK_(a)` of the indicator is `5`?

A

`(1)/(2)`

B

`(1)/(11)`

C

`(10)/(11)`

D

`(1)/(10)`

Text Solution

Verified by Experts

The correct Answer is:
C
`pH=p^(Hin)+log``(In^(-))/(HI_(A))`
`=5+log``(In^(-))/(HI_(A))(In^(-))/(HI_(n))=10`
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