Solubility of `MX_(2)` type electrolytes is `0.5xx10^(-4) mol//L`, then find out `K_(sp)` of electrolytes.

Options

A. `5xx10^(-12)`
B. `25xx10^(-10)`
C. `1xx10^(-13)`
D. `5xx10^(-13)`

Answer

D

Explanation

`underset(Solubility 0.5xx10^(-4)M)(MX_(2)) rarr underset(0.5xx10^(-4)M)(M^(2+))+underset(2xx0.5xx10^(-4)M)(2X^(-))`
(On `100%` ionisation)
` :. K_(sp)` of `MX_(2)=[M^(2+)][X^(-)]^(2)`
`=(0.5xx10^(-4))(1.0xx10^(-4))^(2)`
`=0.5xx10^(-12)=5xx10^(-13)`