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Calculate the pOH of solution at 25^(@)C...

Calculate the `pOH` of solution at `25^(@)C` that contains `1xx10^(-10) M` of hydronium ions, i.e., `H_(3)O^(+)`

A

`4`

B

`9`

C

`1`

D

`7`

Text Solution

Verified by Experts

The correct Answer is:
A
Since `[H_(3)O^(+)]=1xx10^(-10)M` at `25^(@)C[H_(3)O^(+)][OH^(-)]`
`=10^(-14)`
`:. [OH^(-)]=(10^(-14))/(10^(-10))=10^(-4)`
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