Concentration of the `Ag^(+)` ions in a saturated solution of `Ag_(2)CO_(2)O_(4)` is `2.2xx10^(-4) mol L^(-1)` Solubility product of `Ag_(2)C_(2)O_(4)` is:

Options

A. `2.66xx10^(-12)`
B. `4.5xx10^(-11)`
C. `5.3xx10^(-12)`
D. `2.42xx10^(-8)`

Answer

C

Explanation

`Ag_(2)C_(2)O_(4)hArrunderset(2.2xx10^(-4)m)(2Ag^(+))+ underset(1.1xx10^(-4) m)(C_(2)O_(4)^(2-))`
`K_(eq)=[Ag^(+)][C_(2)O_(4)^(2-)]`
`=[2.2xx10^(-4)]^(2).[1.1xx10^(-4)]`
`K_(sp)=5.3xx10^(-12)`
As conc. of `Ag^(+)` is given in question which is double to that of `C_(2)O_(4)^(2-)` so conce. of `C_(2)O_(4)^(2-)` will be `1.1xx10^(-4)M`.