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Solubility product of BaCl(2) is 4xx10^(...

Solubility product of `BaCl_(2)` is `4xx10^(-9)`. Its solubility in moles//litre would be

A

`1xx10^(-3)`

B

`1xx10^(-9)`

C

`4xx10^(-27)`

D

`1xx10^(-27)`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(sp)=4S^(3)`, `S^(3)=(4xx10^(-9))/(4)=10^(-9)`
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