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If K(sp) for HgSO(4) is 6.4xx10^(-5), th...

If `K_(sp)` for `HgSO_(4)` is `6.4xx10^(-5)`, then solubility of this substance in mole per `m^(3)` is

A

`8xx10^(-3)`

B

`8xx10^(-6)`

C

`6.4xx10^(-5)`

D

`6.4xx10^(-27)`

Text Solution

Verified by Experts

The correct Answer is:
A
`HgSO_(4)` of `K_(sp)=S^(2)`
`S=sqrt(K_(sp))` , `S=sqrt(6.4xx10^(-5))` , `S=8xx10^(-3)m//L`.
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