The solubility of `BaSO_(4)` in water is `2.33xx10^(-3) g//litre`. Its solubility product will be (molecular weight of `BaSO_(4)=233`)

Options

A. `1xx10^(-5)`
B. `1xx10^(-10)`
C. `1xx10^(-15)`
D. `1xx10^(-20)`

Answer

B

Explanation

The solubility of `BaSO_(4)` in `g//litre` is given `2.33xx10`
`:.` In mole//litre `n=(W)/(m.wt.)=(2.33xx10^(-3))/(233)`
`=1xx10^(-5)`
Because `BaSO_(4)` is a compound
`K_(sp)=S^(2)=[1xx10^(-5)]^(2)=1xx10^(-10)`