In the reaction : `H_(2)ShArr2H^(+)+S^(--)`, when `NH_(4)OH` is added, then

Options

A. `S^(2-)` is precipitated
B. no action takes place
C. concentration of `S^(2-)` decreases
D. concentration of `S^(2-)` increases

Answer

D

Explanation

In `IV^(th)` group the `S^(2-)` concentration increases when added the `NH_(4)OH` because
`NH_(4)OHhArrNH_(4)^(+)+OH^(-)`
`H_(2)ShArr2H^(+)+S^(2-)`
`OH^(-)+H^(+)hArrH_(2)O`. So that `S^(2-)` is increased.