When `10 ml` of `0.1 M` acitec acid `(pk_(a)=5.0)` is titrated against `10 ml` of `0.1M` ammonia solution `(pk_(b)=5.0)`,the equivalence point occurs at `pH`

Options

A. `5.0`
B. `6.0`
C. `7.0`
D. `9.0`

Answer

C

Explanation

`pK_(a)= -log K_(a)`, `pK_(b)= -log K_(b)`
`pH=(1)/(2)[logK_(a)+logK_(w)-logK_(b)]`
`=-(1)/(2)[-5+log(1xx10^(-14))-(-5)]`
`= -(1)/(2)[-5-14+5]= -(1)/(2)(-14)=7`