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50 mL of 0.1 M solution of a salt reacte...

`50 mL` of `0.1 M` solution of a salt reacted with `25 mL` of `0.1 M` solution of sodium sulphite. The half reaction for the oxidation of sulphite ion is:
`SO_(3)^(2-)(aq)+H_(2)O(l) rarr (aq)+2H^(+)(aq)+2e^(-)`
If the oxidation number of metal in the salt was `3`, what would be the new oxidation number of metal:

A

zero

B

`1`

C

`2`

D

`4`

Text Solution

Verified by Experts

The correct Answer is:
C
No. of equivalent `=mol exxn-fact or`
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