`25 mL` of `0.50M H_(2)O_(2)` solution is added to `50 mL` of `0.20 M KMnO_(4)` is acid solution. Which of the following statements is true?

Options

A. `0.010` mole of oxygen is liberated
B. `0.005` mole of `KMnO_(4)` are left
C. `0.030 g` atom of oxygen gas is evolved
D. `0.0025` mole `H_(2)O_(2)` does not react with `KMnO_(4)`

Answer

B

Explanation

`M` of eq. of `KMnO_(4)=.2xx50xx5=50`
`M` eq. of `H_(2)O_(2)=2xx25xx.5=25`
`M` eq. of `KMnO_(4)` remaining `=(50-25)=25`
Mole of `KMnO_(4)=(25)/(5)xx10^(-3)=5xx10^(-3)=.005`