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An element A in a compound ABD has oxid...

An element `A` in a compound `ABD` has oxidation number `A^(n-)`. It is oxidised by `Cr_(2)O_(7)^(2-)` in acid medium. In the experiment `1.68xx10^(-3)` moles of `K_(2)Cr_(2)O_(7)` were used for `3.26xx10^(-3)` moles of `ABD`. The new oxidation number of `A` after oxidation is:

A

`3`

B

`3-n`

C

`n-3`

D

`+n`

Text Solution

Verified by Experts

The correct Answer is:
B
Meq. Of `K_(2)Cr_(2)O_(7)`= Meq. Of `ABD`
`n-` factor of `K_(2)Cr_(2)O_(7)` in acidic medium `=6`
`6xx1.68xx10^(-3)=x xx3.26xx10^(-3)`
`x=3`
`implies` New oxidation state of `A^(-n)` will be `= -n+3`
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