Moles of `KHC_(2)O_(4)` (potassium acid oxalate) required to reduce 100ml of 0.02M `KMnO_(4)` in acidic medium (to `Mn^(2+)`) is :

Options

A. `x=y`
B. `2x=y`
C. `x=2y`
D. none is correct

Answer

A

Explanation

Eq. of `KMnO_(4)=` Eq. of `KHC_(2)O_(4)`
`:. 100xx10^(-3)xx0.02xx5=(x)/((128)/(1))`
` implies x=1.28 g`
Eq. of `KHC_(2)O_(4)=` Eq. of `Ca(OH)_(2)`
` =(y)/((128)/(1))=100xx10^(-3)xx0.05xx2`
`implies y=1.28 g` `:. X=y`