In alkaline medium, `ClO_(2)` oxidises `H_(2)O_(2) "to" O_(2)` and is itself reduced to `Cl^(ө)`. How many moles of `H_(2)O_(2)` are oxidised by `1 "mol of " ClO_(2)` ?

Options

A. `1.0`
B. `1.5`
C. `2.5`
D. `3.5`

Answer

C

Explanation

`ClO_(2) rarr Cl^(-)`
`ClO_(2)+2H_(2)O+5e rarr Cl^(-)+4OH^(-)`
`H_(2)O rarr O_(2)`
`H_(2)O_(2)+2OH^(-) rarr O_(2)+2H_(2)O+2e`
`ClO_(2)+2H_(2)O+5e rarr Cl^(-)+4OH^(-)]xx2`
`H_(2)O_(2)+2OH^(-) rarr O_(2)+2H_(2)O+2e]xx2`
`2ClO_(2)+5H_(2)O+2OH^(-) rarr 2Cl^(-)+5O_(2)+5H_(2)O`
`2ClO_(2)=5H_(2)O`
`:. ClO_(2)=2.5 H_(2)O_(2)`