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What volume of 3 molar HNO(3) is needed ...

What volume of `3` molar `HNO_(3)` is needed to oxidise `8 g` of `Fe^(3+)`, `HNO_(3)` gets converted to `NO` ?

A

`8 ml`

B

`15.87 ml`

C

`32 ml`

D

`64 ml`

Text Solution

Verified by Experts

The correct Answer is:
B
The balanced reaction is
`underset(1//7)underset(3)(3Fe^(2+))+4H^(+)+NO_(3)^(-) rarr 3Fe^(3+)+underset(3V)underset(1)(NO)+2H_(2)O`
`:. (3)/(1//7)=(1)/(3V)`
`implies V=(1)/(63)L`
`=(1000)/(63)mL=15.87mLl`
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