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HNO(3) oxidies NH(4)^(+) ions to nitroge...

`HNO_(3)` oxidies `NH_(4)^(+)` ions to nitrogen and itself gets reduced to `NO_(2)`. The moles of `HNO_(3)` required by 1 mole of `(NH_(4))_(2)SO_(4)` is:

A

`4`

B

`5`

C

`6`

D

`2`

Text Solution

Verified by Experts

The correct Answer is:
C
`HNO_(3)+NH_(4)^(+) rarr N_(2)+NO_(2)`
Meq of `HNO_(3)=` Meq of `NH_(4)^(+)`
`mol exxn-"factor"=mol exxn-"factor"`
`1xxmol e=1xx6`
`mol e of HNO_(3)=6`
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