What mass of `N_(2)H_(4)` can be oxidised to `N_(2)` by `24 g` of `K_(2)CrO_(4)` which is reduced to `Cr(OH)_(4)^(-)`?

Options

A. `2.969 g`
B. `5.25 g`
C. `9.08 g`
D. `29.69 g`

Answer

A

Explanation

Moles of `K_(2)CrO_(4)` reacted `=(24)/(194)` moles.
`4` moles of `K_(2)CrO_(4)` reacts with `3` moles of `N_(2)H_(4)`
`:. (24)/(194)` moles of `K_(2)CrO_(4)` reacts with `(3)/(4)xx(24)/(194)` moles of
`N_(2)H_(4)`
`:. `Amount of `N_(2)H_(4)` reacted `=(3)/(4)xx(24)/(194)` moles
`=(3)/(4)xx(24)/(194)xx32g=2.969 g`