What weight of `HNO_(3)` is needed to convert `5g` of iodine into iodic acid according to the reaction,
`I_(2)+HNO_(3)rarrHIO_(3)+NO_(2)+H_(2)O`

Options

A. `12.205 g`
B. `24.8 g`
C. `0.248 g`
D. `49.6 g`

Answer

A

Explanation

From the given reaction, the balanced equation is
`I_(2)+10NO_(3)^(-)+8H^(-) rarr 2IO_(3)^(-)+10NO_(3)+4H_(2)O`
From the above equation,
`254 g` of `I_(2)` requires `620 g` of `NO_(3)^(-) ion `
`:. 5 g` of `I_(2)` requires `620` of `NO_(3)^(-)ion=(620xx5)/(254)`
`=12.205 g` of `NO_(3)^(-)`