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Assertion: Equivalent weight of FeC(2)O(...

Assertion: Equivalent weight of `FeC_(2)O_(4)` in the reaction, `FeC_(2)O_(4)+` Oxidising agent `rarr Fe^(3+)+CO_(2)` is `M//3`, where `M` is molar mass of `FeC_(2)O_(4)`.
Reason: In theabove reaction, total two mole of electrons are given up by `1 mol e` of `FeC_(2)O_(4)` to the oxidising agent.

A

If both assertion and reason are true and the reason is the correct explanation of the assertion.

B

If both assertion and reason are true but reason is not the correct explantion of the assertion.

C

If assertion is true but reason is false.

D

If assertion is false but reason is true.

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The correct Answer is:
To solve the problem, we need to analyze the assertion and the reason provided in the question regarding the equivalent weight of `FeC2O4` in the given redox reaction. ### Step-by-Step Solution: 1. **Identify the Reaction**: The reaction given is: \[ \text{FeC}_2\text{O}_4 + \text{Oxidizing agent} \rightarrow \text{Fe}^{3+} + \text{CO}_2 \] 2. **Determine the Oxidation States**: - In `FeC2O4`, iron (Fe) is in the +2 oxidation state (Fe²⁺). - The `C2O4` part (oxalate ion) contains carbon in the +3 oxidation state (each carbon in C2O4 is +3) and the overall charge is -2. 3. **Identify the Changes in Oxidation States**: - Iron (Fe) is oxidized from +2 to +3, losing 1 electron. - The oxalate ion (C2O4²⁻) is oxidized to carbon dioxide (CO2), where each carbon is in the +4 oxidation state, resulting in the loss of 2 electrons. 4. **Calculate Total Electrons Lost**: - Total electrons lost by `FeC2O4`: - 1 electron from Fe (Fe²⁺ to Fe³⁺) - 2 electrons from C2O4 (C2O4²⁻ to CO2) - Therefore, total electrons lost = 1 + 2 = 3 electrons. 5. **Determine the Equivalent Weight**: - The equivalent weight of a substance is given by the formula: \[ \text{Equivalent weight} = \frac{\text{Molar mass}}{\text{n}} \] where `n` is the number of moles of electrons transferred. - Here, `n = 3` (as calculated above). - Let `M` be the molar mass of `FeC2O4`. Thus, the equivalent weight is: \[ \text{Equivalent weight of FeC}_2\text{O}_4 = \frac{M}{3} \] 6. **Conclusion**: - The assertion that the equivalent weight of `FeC2O4` in the reaction is `M/3` is **correct**. - The reason stating that "total two moles of electrons are given up by 1 mole of `FeC2O4`" is **incorrect** because we established that 3 moles of electrons are given up. ### Final Answer: - Assertion: True - Reason: False - Therefore, the answer is that the assertion is true, but the reason is false.
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