In which of the following compounds, nitrogen exhibits the highest oxidation state?

Options

A. `N_(3)H`
B. `NH_(2)OH`
C. `N_(2)H_(4)`
D. `NH_(3)`

Answer

A

Explanation

Let the oxidation state of nitrogen in the given compounds be `x`.
(`a`) `overset(x)(N_(3))overset(+1)(H) implies (x)3+(+1)=0 implies 3x= -1`
`implies x= -(1)/(3)`
(`b`) `overset(x)(N)overset(+1)(H_(2))overset(-2+1)(OH) implies x+(+1)2+(-2)+(+1)=0`
`x+2-2+1=0 implies x= -1`
(`c`) `overset(x)(N_(2))overset(+1)(H_(4)) implies 2(x)+(+1)4=0`
`implies 2x= -4 implies x= -2`
(`d`) `overset(x)(N)overset(+1)(H_(3)) implies x+(+1)3=0`
`x= -3`
`:.` Oxidation state of nitrrogen is highest in `N_(3)H`.