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MnO(4)^(2-) in neutral aqueous medium is...

`MnO_(4)^(2-)` in neutral aqueous medium is disproportionate to

A

`2//3` mole of `MnO_(4)^(-)` and `1//3` mole of `MnO_(2)`

B

`1//3` mole of `MnO_(4)^(-)` and `2//3` mole of `MnO_(2)`

C

`1//3` mole of `Mn_(2)O_(7)` and `1//3` mole of `MnO_(2)`

D

`2//3` mole of `Mn_(2)O_(7)` and `1//3` mole of `MnO_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A

`MnO_(4)^(2-)` in neutral aqueous medium is disproportionate to `(2)/(3)` mole of `MnO_(4)^(-)` and `(1)/(3)` mole of `MnO_(2)`.
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On oxidation of S_(2)O_(3)^(2-) by MnO_(4)^(-) in neutral aqueous medium, the oxidation state of S would change from :

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Knowledge Check

  • MnO_(4)^(2-) (1 mole) in neutral aqueous medium disproportionates to

    A
    2/3 mole of `MnO_(4)^(-) and 1//3` mole of `MnO_(2)`
    B
    1/3 mole of `MnO_(4)^(-) and 2//3` mole of `MnO_(2)`
    C
    1/3 mole of `Mn_(2)O_(7) and 1//3 ` mole of `MnO_(2)`
    D
    2/3 mole of `Mn_(2)O_(7) and 1//3` mole of `MnO_(2)`
  • MnO_(4)^(2-) (1 mole) in neutral aqueous medium disproportionates to :

    A
    2/3 mole `MnO_(4)^(-)` and 1/3 mole `MnO_(2)`
    B
    1/3 mole `MnO_(4)^(-)` and 2/3 mole `MnO_(2)`
    C
    1/3 mole `Mn_(2)O_(7)` and 2/3 mole `MnO_(2)`
    D
    2/3 mole `Mn_(2)O_(7)` and 1/3 mole `MnO_(2)`
  • MnO_(4)^(2-) ( 1 mole) in neutral aqueous medium is disproportionate to

    A
    `2//3` mole of `MnO_(4)^(-)` and `1//3` mole of `MnO_(2)`
    B
    `1//3` mole of `MnO_(4)^(-)` and `2//3` mole of `MnO_(2)`
    C
    `1//3` mole of `Mn_(2)O_(7)` and `1//3` mole of `MnO_(2)`
    D
    `2//3` mole of `Mn_(2)O_(7)` and `1//3` mole of `MnO_(2)`
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    On additon of I^(-) with MnO_(4)^(-) in presence of acidic medium it convert into

    When I^(-) is oxidised by MnO_(4)^(-) in an alkaline medium, I^(-) converts into