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One mole of N(2)H(4) loses ten moles of ...

One mole of `N_(2)H_(4)` loses ten moles of electrons to form a new compound `A`. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in `A`? (There is no change in the oxidation state of hydrogen.)

A

`+3`

B

`-3`

C

`-1`

D

`+5`

Text Solution

Verified by Experts

The correct Answer is:
A
`N_(2)^(2-) rarr 2Na^(+)+10e^(-)`
`:. 2a-[2xx(-2)]=10`
` :.` `a=+3`.
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