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The conductivity of a saturated solution...

The conductivity of a saturated solution of `BaSO_4` is ` 3. 06 xx 10^(-6) "ohm"^(-1) cm^(-1)` and its equivalent conductance is `1.53 "ohm"^(-1) cm^2 equiv^(-1)`. The `K_(sp)` for `BaSO_4` will be .

A

`4xx10^(-12)`

B

`2.5xx10^(-9)`

C

`2.5xx10^(-13)`

D

`4xx10^(-6)`

Text Solution

Verified by Experts

The correct Answer is:
D
`lambda_(m)=(1000K)/(S)=(1000xx3.06xx10^(-6))/(S)=1.53`
`S=2xx10^(-3)(mol)/(litre)`
`K_(sp_((BaSO_(4)))=S_(2)=(2xx10^(-3))^(2)=4xx10^(-6)`
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