The oxidation number of `S` in `H_(2)S_(2)O_(8)` is

Options

A. `+2`
B. `+4`
C. `+6`
D. `+7`

Answer

C

Explanation

The chemical structure of `H_(2)S_(2)O_(8)` is as follows:
`H-overset(O)overset(||)underset(O)underset(||)(O)-S-O-O-S-overset(O)overset(||)underset(O)underset(||)(O)-H`
So the oxidation number of `S` should be:
`underset((for H))(2xx(+1))+underset((for S))(2xx X)+underset((for OforO-O))(6xx(-2))=0` or `X=+6