For the redox reaction
`MnO_(4)^(ө)+C_(2)O_(4)^(2-)+H^(o+)rarrMn^(2+)+CO_(2)+H_(2)O`
the correct coefficients of the reactions for the balanced reaction are

Options

A. (`MnO_(4)^(-)=2`), (`C_(2)O_(4)^(2-)=5`), (`H^(+)=16`)
B. (`MnO_(4)^(-)=16`), (`C_(2)O_(4)^(2-)=5`), (`H^(+)=2`)
C. (`MnO_(4)^(-)=5`), (`C_(2)O_(4)^(2-)=16`), (`H^(+)=2`)
D. (`MnO_(4)^(-)=2`), (`C_(2)O_(4)^(2-)=16`), (`H^(+)=5`)

Answer

A

Explanation

`undersetulbar(2MnO_(4)^(-)+5C_(2)O_(4)^(2-)+16H^(+) rarr 2Mn^(2+)+10CO_(2)+8H_(2)O)(MnO_(4)^(-)+8H^(+)+underset((C_(2)O_(4)^(2) rarr 2CO_(2)+2e)xx5)(5e^(+)toMn^(2+)+8H_(2)Oxx2)`
Thus the coefficent of `MnO_(4)^(-)`, `C_(2)O_(4)^(2-)` and `H^(+)` in the above balanced equation respectively are `2`, `5`, `16`.