Home
Class 11
CHEMISTRY
When the same amount of zinc is treated ...

When the same amount of zinc is treated separately with excess of `H_(2)SO_(4)` and excess of `NaOH`, the ratio of volumes of `H_(2)` evolved is:

A

`1:1`

B

`1:2`

C

`2:1`

D

`9:4`

Text Solution

Verified by Experts

The correct Answer is:
A
`Zn+H_(2)SO_(4)rarr ZnSO_(4)+H_(2)`
`Zn+2NaOHrarr Na_(2)ZnO_(2)+H_(2)`
`:.` Ration of volumes of `H_(2)` evolved is `1:1`.
Promotional Banner

Topper's Solved these Questions

  • HYDROGEN

    A2Z|Exercise Water|53 Videos

  • HYDROGEN

    A2Z|Exercise Hydrogen Peroxide|41 Videos

  • HYDROGEN

    A2Z|Exercise section A Hydrogen|1 Videos

  • HYDROCARBONS

    A2Z|Exercise Section D - Chapter End Test|30 Videos

  • IONIC EQUILIBIUM

    A2Z|Exercise Section D - Chapter End Test|30 Videos

Similar Questions

Explore conceptually related problems

When same amount of zinc is treated separately with excess of H_(2)SO_(4) and NaOH , the ratio of volumes of H_(2) evolved is:

When the same amount of Zn is treated with excess of H_(2)SO_(4) and excess of NaOH separately, the ratio of the volume of hydrogen evolved is-

2g of aluminium is treated, separately with excess of dilute H_(2)SO_(4) , and excess of NaOH , the ratio of volumes of hydrogen evolved is

When the same amount of zinc is treated separately with excess of sulphric acid and excess of sodium hydroxide, the ratio of volume of hydrogen evolved is