From `B_(2)H_(6)`, all the following can be prepared except

Options

A. `B_(2)O_(3)`
B. `H_(3)BO_(3)`
C. `B_(2)(CH_(3))_(6)`
D. `NaBH_(4)`

Explanation

To solve the question, "From B₂H₆, all the following can be prepared except," we need to analyze the possible reactions and products that can be derived from diborane (B₂H₆).

### Step-by-Step Solution:

1. **Understanding B₂H₆ Structure**:
- B₂H₆, or diborane, consists of two boron atoms and six hydrogen atoms. It has a unique structure where two boron atoms are connected by bridging hydrogen atoms.

2. **Oxidation of B₂H₆**:
- When B₂H₆ is oxidized, it can react with oxygen to form boron trioxide (B₂O₃) and water. The balanced reaction is:
\[ B_2H_6 + 3O_2 \rightarrow B_2O_3 + 3H_2O \]
- Thus, B₂O₃ can be prepared from B₂H₆.

3. **Hydrolysis of B₂H₆**:
- B₂H₆ can undergo hydrolysis, which involves the reaction with water to produce boric acid (H₃BO₃) and hydrogen gas (H₂):
\[ B_2H_6 + 6H_2O \rightarrow 2H_3BO_3 + 6H_2 \]
- Therefore, boric acid can also be prepared from B₂H₆.

4. **Formation of Sodium Borohydride (NaBH₄)**:
- When B₂H₆ is treated with sodium hydride (NaH) in the presence of ether, sodium borohydride (NaBH₄) can be formed:
\[ B_2H_6 + 2NaH \rightarrow 2NaBH_4 \]
- Hence, NaBH₄ can also be prepared from B₂H₆.

5. **Attempting to Form B₂CH₆**:
- The question implies the formation of a compound B₂CH₆ by replacing the hydrogen atoms in B₂H₆ with methyl groups (CH₃). However, only the terminal hydrogen atoms can be replaced with methyl groups, while the bridging hydrogen atoms cannot be replaced due to their bonding nature.
- Therefore, B₂CH₆ cannot be formed from B₂H₆.

### Conclusion:
From the analysis, we conclude that B₂H₆ can yield B₂O₃, H₃BO₃, and NaBH₄, but it cannot yield B₂CH₆. Thus, the answer is:

**B₂CH₆ cannot be prepared from B₂H₆.**