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The dissolution of Al(OH)(3) by a soluti...

The dissolution of `Al(OH)_(3)` by a solution of `NaOH` results in the formation of

A

`[Al(H_(2)O)_(2)(OH)_(4)]^(-)`

B

`[Al(H_(2)O)_(4)(OH)]^(2+)`

C

`[Al(H_(2)O)_(3)(OH)_(3)]`

D

`[Al(H_(2)O)_(6)(OH)_(3)]`

Text Solution

Verified by Experts

The correct Answer is:
A
`Al(OH)_(3)+OH^(-)to[Al(OH)_(4)^(-)]`.
Coordinate number is `6`, thus, it exist as
`[Al(H_(2)O)_(2)(OH)_(4)]^(-)`
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