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The electron of a hydrogen atom revolves...

The electron of a hydrogen atom revolves the proton in a circuit nth of radius `r_(0) = (in_(0) n^(2)h^(2))/(pi m e^(2)) ` with a speed `upsilon_(0) =(e^(2))/(2 in_(0) nh)` The current to circulating charge is proportional to

A

`e^(2)`

B

`e^(3)`

C

`e^(5)`

D

`e^(6)`

Text Solution

Verified by Experts

The correct Answer is:
C

`T = ("distance")/("speed") = (2pir_(n))/(v_(d))`
`= (2pi in_(0) h^(2) xx 2 in_(0) nh)/(pi m e^(2) xx e^(2)) = (4 in_(0)^(2) n^(3)h^(3))/(m e^(4))`
Current `I =(e)/(T) = ( e xx me^(4))/(4 in_(0)^(2)n^(2)h^(3)) = (m e^(5))/(4 in_(0)^(2)n^(2)h^(3))`
so `I prop e^(5)`
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