Two capacitors A and B of capacitances `2muF` and `5 mu F` are connected to two battery as shown in figure The potential difference in volt between the plate of A is

Options

A. 2
B. 5
C. 7
D. 18

Answer

b

Explanation

Let `Q` b ethe charge stored in each capactor. Then
`18 - 11 = (Q)/(2 mu F) + (Q)/(5 mu F) = (7Q)/(10mu F)`
or `Q = 10 mu C`
Pot. Diff. across capactior A
`V_(A) = (Q)/(C_(A))= (10muC)/(2 muF) = 5V`